Q#1 1. The  normality p-value for population a is 56.83% and for b it is
       80.38%. Therefore, normality is reasonable for each population.
    2. Since 76.857 < 82.714 then our sample means are consistent with
       Ha.
    3. From the ttest output the p-value for the equal variance 
       hypotheses is 61.89 and so we can conclude that the population 
       variances are equal.
    4. Since the population variances are equal, the p-value for the
       stated hypotheses is 0.24%. Remember that this is a two sided
       p-value and so, since our alternative is one sided, our p-value
       is 0.12%. This is highly significant and we reject H0 and 
       conclude that mu(ya) is less than mu(yb).


Q#2 1. The  normality p-value for population a is 0.36% and for b it 
       is 0.26%. Therefore, normality is not reasonable for either 
       population.
    2. Since normality is not reasonable, the ttest output cannot be 
       used. The side by side box plots suggest that it is reasonable 
       to conclude that the populations are approximately the same shape 
       and so we may use the output from npar1way to determine the 
       p-value for the stated hypotheses. The p-value is 7.4% and so we 
       have insufficient evidence to reject H0 and conclude that, given 
       the evidence, it is reasonable to say that mu(ya) is equal to 
       mu(yb).