1. Determine the value of z when each of the algorithm segments below is
   executed.

   a)  x := 1
       y := 0
       if (x > 2) then
          y := 2 * x
       endif
       z := 3 * y

   b)  i := 2
       if ((i > 1) and (i < 0)) then
          z := 4
       else
          z := 8
       endif

   c)  i := 2
       if ((i < 3) or (i > 5)) then
          z := 1
       else
          z := 0
       endif

   d)  x := 0
       y := 1
       if ((x < y) and (y > 0)) then
          y := y + 1
          x := x + 1
       endif
       z := x * y

   e)  x := 0
       y := 4
       if (y > 4) then
          if (x < 1) then
             x := x + 1
          endif  
          z := x * y 
       else
          if (x < 1) then
             x := x + 2
          else
             x := x + 1
          endif
          z := (x * y) + 1
       endif
 


2. Consider the algorithm below:

   q := 0
   r := a
   while (r >= d) do
      r := r - d
      q := q + 1
   endwhile

   Determine the values of q and r if prior to execution a and d have the
   values given below:

   a) a = 30, d = 7
   b) a = 23, d = 4
   c) a = 28, d = 9 



3. Determine the value of s when each of the algorithm segments below is
   executed.

   a)  i := 0
       s := 0
       while (i < 3) do
          s := s + i
          i := i + 1
       endwhile

   b)  i := 0
       s := 1
       while (i < 2) do
          s := 3 * s
          i := i + 1
       endwhile

   c)  i := 1
       s := 0
       while (i < 5) do
          if ((i = 2) or (i = 4)) then
             i := i + 1
          else
             s := s + i
             i := i + 1
          endif
       endwhile

   d)  x := 1
       y := 1
       s := 0
       while (x < 3) do
          while (y < 3) do
             s := s + y 
             y := y + 1
          endwhile
          y := 1
          s := s + x
          x := x + 1
       endwhile

   e)  x := 0
       y := 1
       s := 2
       while (x < 2) do
          while (y < 1) do
             s := s + y 
             y := y + 1
          endwhile
          y := 1
          x := x + 1
       endwhile