Lookup a 4 byte integer at address 0x08048088. Assume the machine is little endian.

         hex > 0x08048088
      binary > 0000 1000 0000 0100 1000 0000 1000 1000
      T:S:B  > 0000 1000 0000 0100 10:00 0000 100:0 1000
          T  > 00 0010 0000 0001 0010 = 0x02012
          S  > 0 0000 0100 = 0x004 = 4
          B  > 0 1000 = 0x08
     

So look in set S = 4 and compare the tag in the (only) line of set 4 with 0x02012.

1. Suppose the first 16 bytes of the data block of the line in set 4 of the cache is

   Tag: 0x2012

   Block data: 01 02 00 00 FF FF FF FF EF BE AD DE 01 02 03 04

   So address 0x08048090 is a cache hit

   Since B = 8, the integer data starts at byte offset 8 in the block data.

   Integers are 4 bytes and the bytes are stored in reverse order on little endian machines.

   So the integer value is 0xDEADBEEF

2. If the cache line had been:

   Tag: 0x2080

   Block data: 01 02 00 00 FF FF FF FF EF BE AD DE 01 02 03 04

   The tag would not match and address 0x08048090 would be a cache miss.